(6x-5)/4=(x+1)/2

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Solution for (6x-5)/4=(x+1)/2 equation: 



(6x-5)/4=(x+1)/2

We move all terms to the left:

(6x-5)/4-((x+1)/2)=0

We calculate fractions


6x/()+(-((x+1)*4)/()=0



We calculate terms in parentheses: +(-((x+1)*4)/(), so:

-((x+1)*4)/(

We multiply all the terms by the denominator


-((x+1)*4)



We calculate terms in parentheses: -((x+1)*4), so:

(x+1)*4

We multiply parentheses

4x+4

Back to the equation:

-(4x+4)



We get rid of parentheses

-4x-4

Back to the equation:

+(-4x-4)



We get rid of parentheses

6x/()-4x-4=0

We multiply all the terms by the denominator


6x-4x*()-4*()=0

We add all the numbers together, and all the variables

6x-4x*()=0

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