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(6x-5=-3(2x+1))
We move all terms to the left:
(6x-5-(-3(2x+1)))=0
We calculate terms in parentheses: +(6x-5-(-3(2x+1))), so:We get rid of parentheses
6x-5-(-3(2x+1))
determiningTheFunctionDomain 6x-(-3(2x+1))-5
We calculate terms in parentheses: -(-3(2x+1)), so:We get rid of parentheses
-3(2x+1)
We multiply parentheses
-6x-3
Back to the equation:
-(-6x-3)
6x+6x+3-5
We add all the numbers together, and all the variables
12x-2
Back to the equation:
+(12x-2)
12x-2=0
We move all terms containing x to the left, all other terms to the right
12x=2
x=2/12
x=1/6
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