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(6x-6)(5x+1)=0
We multiply parentheses ..
(+30x^2+6x-30x-6)=0
We get rid of parentheses
30x^2+6x-30x-6=0
We add all the numbers together, and all the variables
30x^2-24x-6=0
a = 30; b = -24; c = -6;
Δ = b2-4ac
Δ = -242-4·30·(-6)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-36}{2*30}=\frac{-12}{60} =-1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+36}{2*30}=\frac{60}{60} =1 $
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