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(6x-6)(7x+1)=0
We multiply parentheses ..
(+42x^2+6x-42x-6)=0
We get rid of parentheses
42x^2+6x-42x-6=0
We add all the numbers together, and all the variables
42x^2-36x-6=0
a = 42; b = -36; c = -6;
Δ = b2-4ac
Δ = -362-4·42·(-6)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-48}{2*42}=\frac{-12}{84} =-1/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+48}{2*42}=\frac{84}{84} =1 $
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