(6x-6)(8x+2)=0

Solution for (6x-6)(8x+2)=0 equation:

(6x-6)(8x+2)=0

We multiply parentheses ..

(+48x^2+12x-48x-12)=0

We get rid of parentheses

48x^2+12x-48x-12=0

We add all the numbers together, and all the variables

48x^2-36x-12=0

a = 48; b = -36; c = -12;
Δ = b2-4ac
Δ = -362-4·48·(-12)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-60}{2*48}=\frac{-24}{96}
=-1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+60}{2*48}=\frac{96}{96}
=1
$