(6x-6)/4=(3x+18)/9

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Solution for (6x-6)/4=(3x+18)/9 equation: 



(6x-6)/4=(3x+18)/9

We move all terms to the left:

(6x-6)/4-((3x+18)/9)=0

We calculate fractions


6x/()+(-((3x+18)*4)/()=0



We calculate terms in parentheses: +(-((3x+18)*4)/(), so:

-((3x+18)*4)/(

We multiply all the terms by the denominator


-((3x+18)*4)



We calculate terms in parentheses: -((3x+18)*4), so:

(3x+18)*4

We multiply parentheses

12x+72

Back to the equation:

-(12x+72)



We get rid of parentheses

-12x-72

Back to the equation:

+(-12x-72)



We get rid of parentheses

6x/()-12x-72=0

We multiply all the terms by the denominator


6x-12x*()-72*()=0

We add all the numbers together, and all the variables

6x-12x*()=0

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