(6x-6-16x)/24=(4-3x)/12

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Solution for (6x-6-16x)/24=(4-3x)/12 equation: 



(6x-6-16x)/24=(4-3x)/12

We move all terms to the left:

(6x-6-16x)/24-((4-3x)/12)=0

We add all the numbers together, and all the variables

(-10x-6)/24-((-3x+4)/12)=0

We calculate fractions


(-10x)/()+(-((-3x+4)*24)/()=0



We calculate terms in parentheses: +(-((-3x+4)*24)/(), so:

-((-3x+4)*24)/(

We multiply all the terms by the denominator


-((-3x+4)*24)



We calculate terms in parentheses: -((-3x+4)*24), so:

(-3x+4)*24

We multiply parentheses

-72x+96

Back to the equation:

-(-72x+96)



We get rid of parentheses

72x-96

Back to the equation:

+(72x-96)



We get rid of parentheses

(-10x)/()+72x-96=0

We multiply all the terms by the denominator


(-10x)+72x*()-96*()=0

We add all the numbers together, and all the variables

(-10x)+72x*()=0

We get rid of parentheses

-10x+72x*()=0

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