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(6x-7)(2x+8)=0
We multiply parentheses ..
(+12x^2+48x-14x-56)=0
We get rid of parentheses
12x^2+48x-14x-56=0
We add all the numbers together, and all the variables
12x^2+34x-56=0
a = 12; b = 34; c = -56;
Δ = b2-4ac
Δ = 342-4·12·(-56)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3844}=62$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-62}{2*12}=\frac{-96}{24} =-4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+62}{2*12}=\frac{28}{24} =1+1/6 $
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