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(6x-7)(3x+1)=0
We multiply parentheses ..
(+18x^2+6x-21x-7)=0
We get rid of parentheses
18x^2+6x-21x-7=0
We add all the numbers together, and all the variables
18x^2-15x-7=0
a = 18; b = -15; c = -7;
Δ = b2-4ac
Δ = -152-4·18·(-7)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-27}{2*18}=\frac{-12}{36} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+27}{2*18}=\frac{42}{36} =1+1/6 $
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