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(6x-7)(4x-1)=0
We multiply parentheses ..
(+24x^2-6x-28x+7)=0
We get rid of parentheses
24x^2-6x-28x+7=0
We add all the numbers together, and all the variables
24x^2-34x+7=0
a = 24; b = -34; c = +7;
Δ = b2-4ac
Δ = -342-4·24·7
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-22}{2*24}=\frac{12}{48} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+22}{2*24}=\frac{56}{48} =1+1/6 $
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