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(6x-7)(5x+16)=180
We move all terms to the left:
(6x-7)(5x+16)-(180)=0
We multiply parentheses ..
(+30x^2+96x-35x-112)-180=0
We get rid of parentheses
30x^2+96x-35x-112-180=0
We add all the numbers together, and all the variables
30x^2+61x-292=0
a = 30; b = 61; c = -292;
Δ = b2-4ac
Δ = 612-4·30·(-292)
Δ = 38761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-\sqrt{38761}}{2*30}=\frac{-61-\sqrt{38761}}{60} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+\sqrt{38761}}{2*30}=\frac{-61+\sqrt{38761}}{60} $
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