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(6x-7)(5x=4)=0
We move all terms to the left:
(6x-7)(5x-(4))=0
We multiply parentheses ..
(+30x^2-24x-35x+28)=0
We get rid of parentheses
30x^2-24x-35x+28=0
We add all the numbers together, and all the variables
30x^2-59x+28=0
a = 30; b = -59; c = +28;
Δ = b2-4ac
Δ = -592-4·30·28
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:x_{1}=\frac{-b-\sqrt{\Delta}}{2a}x_{2}=\frac{-b+\sqrt{\Delta}}{2a}\sqrt{\Delta}=\sqrt{121}=11x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-11}{2*30}=\frac{48}{60} =4/5x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+11}{2*30}=\frac{70}{60} =1+1/6
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