(6x-7)+(4x-2)=141

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Solution for (6x-7)+(4x-2)=141 equation: 



(6x-7)+(4x-2)=141

We move all terms to the left:

(6x-7)+(4x-2)-(141)=0

We get rid of parentheses

6x+4x-7-2-141=0

We add all the numbers together, and all the variables

10x-150=0

We move all terms containing x to the left, all other terms to the right

10x=150

x=150/10

x=15

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