(6x-7)=(2x+41)

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Solution for (6x-7)=(2x+41) equation: 



(6x-7)=(2x+41)

We move all terms to the left:

(6x-7)-((2x+41))=0

We get rid of parentheses

6x-((2x+41))-7=0



We calculate terms in parentheses: -((2x+41)), so:

(2x+41)

We get rid of parentheses

2x+41

Back to the equation:

-(2x+41)



We get rid of parentheses

6x-2x-41-7=0

We add all the numbers together, and all the variables

4x-48=0

We move all terms containing x to the left, all other terms to the right

4x=48

x=48/4

x=12

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