(6x-8)(9x+7)=0

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Solution for (6x-8)(9x+7)=0 equation:



(6x-8)(9x+7)=0
We multiply parentheses ..
(+54x^2+42x-72x-56)=0
We get rid of parentheses
54x^2+42x-72x-56=0
We add all the numbers together, and all the variables
54x^2-30x-56=0
a = 54; b = -30; c = -56;
Δ = b2-4ac
Δ = -302-4·54·(-56)
Δ = 12996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12996}=114$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-114}{2*54}=\frac{-84}{108} =-7/9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+114}{2*54}=\frac{144}{108} =1+1/3 $

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