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(6x-9)(6x+9)=0
We use the square of the difference formula
36x^2-81=0
a = 36; b = 0; c = -81;
Δ = b2-4ac
Δ = 02-4·36·(-81)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11664}=108$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-108}{2*36}=\frac{-108}{72} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+108}{2*36}=\frac{108}{72} =1+1/2 $
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