(6x-9)+((x-3)(x-3))=x*x

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Solution for (6x-9)+((x-3)(x-3))=x*x equation: 



(6x-9)+((x-3)(x-3))=x*x

We move all terms to the left:

(6x-9)+((x-3)(x-3))-(x*x)=0

We add all the numbers together, and all the variables

(6x-9)+((x-3)(x-3))-(+x*x)=0

We get rid of parentheses

6x+((x-3)(x-3))-x*x-9=0

We multiply parentheses ..

((+x^2-3x-3x+9))+6x-x*x-9=0



We calculate terms in parentheses: +((+x^2-3x-3x+9)), so:

(+x^2-3x-3x+9)

We get rid of parentheses

x^2-3x-3x+9

We add all the numbers together, and all the variables

x^2-6x+9

Back to the equation:

+(x^2-6x+9)



We add all the numbers together, and all the variables

6x+(x^2-6x+9)-x*x-9=0

Wy multiply elements

-1x^2+6x+(x^2-6x+9)-9=0

We get rid of parentheses

-1x^2+x^2+6x-6x+9-9=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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