(6x/36)+((5/15)x)=62

Solution for (6x/36)+((5/15)x)=62 equation:

(6x/36)+((5/15)x)=62

We move all terms to the left:

(6x/36)+((5/15)x)-(62)=0


Domain of the equation: 15)x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+6x/36)+((+5/15)x)-62=0

We get rid of parentheses

6x/36+((+5/15)x)-62=0

We calculate fractions


90x^2/540x+()/540x-62=0

We multiply all the terms by the denominator


90x^2-62*540x+()=0

We add all the numbers together, and all the variables

90x^2-62*540x=0

Wy multiply elements

90x^2-33480x=0

a = 90; b = -33480; c = 0;
Δ = b2-4ac
Δ = -334802-4·90·0
Δ = 1120910400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1120910400}=33480$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33480)-33480}{2*90}=\frac{0}{180}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33480)+33480}{2*90}=\frac{66960}{180}
=372
$