(6x/4)+3x=72

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Solution for (6x/4)+3x=72 equation:



(6x/4)+3x=72
We move all terms to the left:
(6x/4)+3x-(72)=0
We add all the numbers together, and all the variables
(+6x/4)+3x-72=0
We add all the numbers together, and all the variables
3x+(+6x/4)-72=0
We get rid of parentheses
3x+6x/4-72=0
We multiply all the terms by the denominator
3x*4+6x-72*4=0
We add all the numbers together, and all the variables
6x+3x*4-288=0
Wy multiply elements
6x+12x-288=0
We add all the numbers together, and all the variables
18x-288=0
We move all terms containing x to the left, all other terms to the right
18x=288
x=288/18
x=16

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