(6x/5)-7=41

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Solution for (6x/5)-7=41 equation:



(6x/5)-7=41
We move all terms to the left:
(6x/5)-7-(41)=0
We add all the numbers together, and all the variables
(+6x/5)-7-41=0
We add all the numbers together, and all the variables
(+6x/5)-48=0
We get rid of parentheses
6x/5-48=0
We multiply all the terms by the denominator
6x-48*5=0
We add all the numbers together, and all the variables
6x-240=0
We move all terms containing x to the left, all other terms to the right
6x=240
x=240/6
x=40

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