(6y+10)/3=(2y-6)/5

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Solution for (6y+10)/3=(2y-6)/5 equation: 



(6y+10)/3=(2y-6)/5

We move all terms to the left:

(6y+10)/3-((2y-6)/5)=0

We calculate fractions


6y/()+(-((2y-6)*3)/()=0



We calculate terms in parentheses: +(-((2y-6)*3)/(), so:

-((2y-6)*3)/(

We multiply all the terms by the denominator


-((2y-6)*3)



We calculate terms in parentheses: -((2y-6)*3), so:

(2y-6)*3

We multiply parentheses

6y-18

Back to the equation:

-(6y-18)



We get rid of parentheses

-6y+18

Back to the equation:

+(-6y+18)



We get rid of parentheses

6y/()-6y+18=0

We multiply all the terms by the denominator


6y-6y*()+18*()=0

We add all the numbers together, and all the variables

6y-6y*()=0

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