(6y+2)=-2(2y-1)

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Solution for (6y+2)=-2(2y-1) equation: 



(6y+2)=-2(2y-1)

We move all terms to the left:

(6y+2)-(-2(2y-1))=0

We get rid of parentheses

6y-(-2(2y-1))+2=0



We calculate terms in parentheses: -(-2(2y-1)), so:

-2(2y-1)

We multiply parentheses

-4y+2

Back to the equation:

-(-4y+2)



We get rid of parentheses

6y+4y-2+2=0

We add all the numbers together, and all the variables

10y=0

y=0/10

y=0

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