(6y+5)+(3y+4)=11y-3

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Solution for (6y+5)+(3y+4)=11y-3 equation: 



(6y+5)+(3y+4)=11y-3

We move all terms to the left:

(6y+5)+(3y+4)-(11y-3)=0

We get rid of parentheses

6y+3y-11y+5+4+3=0

We add all the numbers together, and all the variables

-2y+12=0

We move all terms containing y to the left, all other terms to the right

-2y=-12

y=-12/-2

y=+6

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