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(6y-1)(y+5)=15y-9
We move all terms to the left:
(6y-1)(y+5)-(15y-9)=0
We get rid of parentheses
(6y-1)(y+5)-15y+9=0
We multiply parentheses ..
(+6y^2+30y-1y-5)-15y+9=0
We get rid of parentheses
6y^2+30y-1y-15y-5+9=0
We add all the numbers together, and all the variables
6y^2+14y+4=0
a = 6; b = 14; c = +4;
Δ = b2-4ac
Δ = 142-4·6·4
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-10}{2*6}=\frac{-24}{12} =-2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+10}{2*6}=\frac{-4}{12} =-1/3 $
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