(6y-5)=(3y+7)

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Solution for (6y-5)=(3y+7) equation: 



(6y-5)=(3y+7)

We move all terms to the left:

(6y-5)-((3y+7))=0

We get rid of parentheses

6y-((3y+7))-5=0



We calculate terms in parentheses: -((3y+7)), so:

(3y+7)

We get rid of parentheses

3y+7

Back to the equation:

-(3y+7)



We get rid of parentheses

6y-3y-7-5=0

We add all the numbers together, and all the variables

3y-12=0

We move all terms containing y to the left, all other terms to the right

3y=12

y=12/3

y=4

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