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(6y-5)=2(10+3y)
We move all terms to the left:
(6y-5)-(2(10+3y))=0
We add all the numbers together, and all the variables
(6y-5)-(2(3y+10))=0
We get rid of parentheses
6y-(2(3y+10))-5=0
We calculate terms in parentheses: -(2(3y+10)), so:We get rid of parentheses
2(3y+10)
We multiply parentheses
6y+20
Back to the equation:
-(6y+20)
6y-6y-20-5=0
We add all the numbers together, and all the variables
-25!=0
There is no solution for this equation
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