(6y-5)=2(10+3y)

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Solution for (6y-5)=2(10+3y) equation: 



(6y-5)=2(10+3y)

We move all terms to the left:

(6y-5)-(2(10+3y))=0

We add all the numbers together, and all the variables

(6y-5)-(2(3y+10))=0

We get rid of parentheses

6y-(2(3y+10))-5=0



We calculate terms in parentheses: -(2(3y+10)), so:

2(3y+10)

We multiply parentheses

6y+20

Back to the equation:

-(6y+20)



We get rid of parentheses

6y-6y-20-5=0

We add all the numbers together, and all the variables

-25!=0

There is no solution for this equation

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