(6y-8)(2y+8)=0

Solution for (6y-8)(2y+8)=0 equation:

(6y-8)(2y+8)=0

We multiply parentheses ..

(+12y^2+48y-16y-64)=0

We get rid of parentheses

12y^2+48y-16y-64=0

We add all the numbers together, and all the variables

12y^2+32y-64=0

a = 12; b = 32; c = -64;
Δ = b2-4ac
Δ = 322-4·12·(-64)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-64}{2*12}=\frac{-96}{24}
=-4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+64}{2*12}=\frac{32}{24}
=1+1/3
$