(6z)/(z+2)=2

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Solution for (6z)/(z+2)=2 equation: 


D( z )

z+2 = 0

z+2 = 0

z+2 = 0

z+2 = 0 // - 2

z = -2

z in (-oo:-2) U (-2:+oo)

(6*z)/(z+2) = 2 // - 2

(6*z)/(z+2)-2 = 0

(6*z)/(z+2)+(-2*(z+2))/(z+2) = 0

6*z-2*(z+2) = 0

4*z-4 = 0

(4*z-4)/(z+2) = 0

(4*z-4)/(z+2) = 0 // * z+2

4*z-4 = 0

4*z-4 = 0 // + 4

4*z = 4 // : 4

z = 4/4

z = 1

z = 1

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