(6z-32)=106

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Solution for (6z-32)=106 equation: 



(6z-32)=106

We move all terms to the left:

(6z-32)-(106)=0

We get rid of parentheses

6z-32-106=0

We add all the numbers together, and all the variables

6z-138=0

We move all terms containing z to the left, all other terms to the right

6z=138

z=138/6

z=23

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