(7)2(b+3)=4b-2

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Solution for (7)2(b+3)=4b-2 equation: 



(7)2(b+3)=4b-2

We move all terms to the left:

(7)2(b+3)-(4b-2)=0

We multiply parentheses

72b-(4b-2)+216=0

We get rid of parentheses

72b-4b+2+216=0

We add all the numbers together, and all the variables

68b+218=0

We move all terms containing b to the left, all other terms to the right

68b=-218

b=-218/68

b=-3+7/34

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