(7+-2)-1(3t+1)=-3(1+3t)

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Solution for (7+-2)-1(3t+1)=-3(1+3t) equation: 



(7+-2)-1(3t+1)=-3(1+3t)

We move all terms to the left:

(7+-2)-1(3t+1)-(-3(1+3t))=0

We add all the numbers together, and all the variables

-1(3t+1)-(-3(3t+1))+5=0



We calculate terms in parentheses: -(-3(3t+1)), so:

-3(3t+1)

We multiply parentheses

-9t-3

Back to the equation:

-(-9t-3)



We get rid of parentheses

-1(3t+1)+9t+3+5=0

We add all the numbers together, and all the variables

9t-1(3t+1)+8=0

We move all terms containing t to the left, all other terms to the right

9t-1(3t+1)=-8

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