(7+2(x+1))/3=8x/5

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Solution for (7+2(x+1))/3=8x/5 equation: 


x in (-oo:+oo)

(2*(x+1)+7)/3 = (8*x)/5 // - (8*x)/5

(2*(x+1)+7)/3-((8*x)/5) = 0

(2*(x+1)+7)/3+(-8/5)*x = 0

(2*(x+1)+7)/3+(-8*x)/5 = 0

(5*(2*(x+1)+7))/(3*5)+(-8*3*x)/(3*5) = 0

5*(2*(x+1)+7)-8*3*x = 0

45-14*x = 0

(45-14*x)/(3*5) = 0

(45-14*x)/(3*5) = 0 // * 3*5

45-14*x = 0

45-14*x = 0 // - 45

-14*x = -45 // : -14

x = -45/(-14)

x = 45/14

x = 45/14

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