(7+2i)(2+3i)=0

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Solution for (7+2i)(2+3i)=0 equation:


Simplifying
(7 + 2i)(2 + 3i) = 0

Multiply (7 + 2i) * (2 + 3i)
(7(2 + 3i) + 2i * (2 + 3i)) = 0
((2 * 7 + 3i * 7) + 2i * (2 + 3i)) = 0
((14 + 21i) + 2i * (2 + 3i)) = 0
(14 + 21i + (2 * 2i + 3i * 2i)) = 0
(14 + 21i + (4i + 6i2)) = 0

Combine like terms: 21i + 4i = 25i
(14 + 25i + 6i2) = 0

Solving
14 + 25i + 6i2 = 0

Solving for variable 'i'.

Factor a trinomial.
(7 + 2i)(2 + 3i) = 0

Subproblem 1

Set the factor '(7 + 2i)' equal to zero and attempt to solve: Simplifying 7 + 2i = 0 Solving 7 + 2i = 0 Move all terms containing i to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + 2i = 0 + -7 Combine like terms: 7 + -7 = 0 0 + 2i = 0 + -7 2i = 0 + -7 Combine like terms: 0 + -7 = -7 2i = -7 Divide each side by '2'. i = -3.5 Simplifying i = -3.5

Subproblem 2

Set the factor '(2 + 3i)' equal to zero and attempt to solve: Simplifying 2 + 3i = 0 Solving 2 + 3i = 0 Move all terms containing i to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + 3i = 0 + -2 Combine like terms: 2 + -2 = 0 0 + 3i = 0 + -2 3i = 0 + -2 Combine like terms: 0 + -2 = -2 3i = -2 Divide each side by '3'. i = -0.6666666667 Simplifying i = -0.6666666667

Solution

i = {-3.5, -0.6666666667}

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