(7+2x)*2+(x+3)*2+(5x-14)=50

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Solution for (7+2x)*2+(x+3)*2+(5x-14)=50 equation:


(7+2x)*2+(x+3)*2+(5x-14)=50

We simplify the equation to the form, which is simple to understand 
(7+2x)*2+(x+3)*2+(5x-14)=50

Reorder the terms in parentheses
(+14+4x)+(x+3)*2+(5x-14)=50

Remove unnecessary parentheses
+14+4x+(x+3)*2+(5x-14)=50

Reorder the terms in parentheses
+14+4x+(+2x+6)+(5x-14)=50

Remove unnecessary parentheses
+14+4x+2x+6+(+5x-14+)=+50

Remove unnecessary parentheses
+14+4x+2x+6+5x-14=+50

We move all terms containing x to the left and all other terms to the right. 
+4x+2x+5x=+50-14-6+14

We simplify left and right side of the equation. 
+11x=+44

We divide both sides of the equation by 11 to get x. 
x=4

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