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(7+35)7=x2

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Solution for (7+35)7=x2 equation:



(7+35)7=x2
We move all terms to the left:
(7+35)7-(x2)=0
We add all the numbers together, and all the variables
-x2+427=0
We add all the numbers together, and all the variables
-1x^2+427=0
a = -1; b = 0; c = +427;
Δ = b2-4ac
Δ = 02-4·(-1)·427
Δ = 1708
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}

The end solution:
\sqrt{\Delta}=\sqrt{1708}=\sqrt{4*427}=\sqrt{4}*\sqrt{427}=2\sqrt{427}
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{427}}{2*-1}=\frac{0-2\sqrt{427}}{-2} =-\frac{2\sqrt{427}}{-2} =-\frac{\sqrt{427}}{-1}
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{427}}{2*-1}=\frac{0+2\sqrt{427}}{-2} =\frac{2\sqrt{427}}{-2} =\frac{\sqrt{427}}{-1}

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