(7+3x)+(7+3x)+(2x+5)=83

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Solution for (7+3x)+(7+3x)+(2x+5)=83 equation: 



(7+3x)+(7+3x)+(2x+5)=83

We move all terms to the left:

(7+3x)+(7+3x)+(2x+5)-(83)=0

We add all the numbers together, and all the variables

(3x+7)+(3x+7)+(2x+5)-83=0

We get rid of parentheses

3x+3x+2x+7+7+5-83=0

We add all the numbers together, and all the variables

8x-64=0

We move all terms containing x to the left, all other terms to the right

8x=64

x=64/8

x=8

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