(7+7/9)k-9=2k

Solution for (7+7/9)k-9=2k equation:

(7+7/9)k-9=2k

We move all terms to the left:

(7+7/9)k-9-(2k)=0


Domain of the equation: 9)k!=0

k!=0/1

k!=0

k∈R


We add all the numbers together, and all the variables

(7/9+7)k-2k-9=0

We add all the numbers together, and all the variables

-2k+(7/9+7)k-9=0

We multiply parentheses

7k^2-2k+7k-9=0

We add all the numbers together, and all the variables

7k^2+5k-9=0

a = 7; b = 5; c = -9;
Δ = b2-4ac
Δ = 52-4·7·(-9)
Δ = 277
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{277}}{2*7}=\frac{-5-\sqrt{277}}{14}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{277}}{2*7}=\frac{-5+\sqrt{277}}{14}
$