(7+7/x)(y+3/7)=65+5/9

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Solution for (7+7/x)(y+3/7)=65+5/9 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(7/x+7)*(y+3/7) = 5/9+65 // - 5/9+65

(7/x+7)*(y+3/7)-(5/9)-65 = 0

(7/x+7)*(y+3/7)-5/9-65 = 0

(7*x^-1+7)*(y+3/7)-5/9-65 = 0

(9*(7*x^-1+7)*(y+3/7))/9-5/9+(-65*9)/9 = 0

9*(7*x^-1+7)*(y+3/7)-65*9-5 = 0

27*x^-1+63*x^-1*y+63*y-585+22 = 0

27*x^-1+63*x^-1*y+63*y-563 = 0

27*x^-1+63*x^-1*y+63*y-563 = 0

27*x^-1-563*x^0 = 0

(27*x^0-563*x^1)/(x^1) = 0 // * x^2

x^1*(27*x^0-563*x^1) = 0

x^1

27-563*x = 0

-563*x^1 = -27 // : -563

x^1 = 27/563

x = 27/563

x in { 27/563}

x-27/563 = 0

(x-27/563)/9 = 0

(x-27/563)/9 = 0 // * 9

x-27/563 = 0

x-27/563 = 0 // + 27/563

x = 27/563

x = 27/563

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