(7+8)=2(t+1)+2

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Solution for (7+8)=2(t+1)+2 equation: 



(7+8)=2(t+1)+2

We move all terms to the left:

(7+8)-(2(t+1)+2)=0

We add all the numbers together, and all the variables

-(2(t+1)+2)+15=0



We calculate terms in parentheses: -(2(t+1)+2), so:

2(t+1)+2

We multiply parentheses

2t+2+2

We add all the numbers together, and all the variables

2t+4

Back to the equation:

-(2t+4)



We get rid of parentheses

-2t-4+15=0

We add all the numbers together, and all the variables

-2t+11=0

We move all terms containing t to the left, all other terms to the right

-2t=-11

t=-11/-2

t=5+1/2

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