(7+9i)(7+9i)=0

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Solution for (7+9i)(7+9i)=0 equation: 



(7+9i)(7+9i)=0

We add all the numbers together, and all the variables

(9i+7)(9i+7)=0

We multiply parentheses ..

(+81i^2+63i+63i+49)=0

We get rid of parentheses

81i^2+63i+63i+49=0

We add all the numbers together, and all the variables

81i^2+126i+49=0

a = 81; b = 126; c = +49;
Δ = b2-4ac
Δ = 1262-4·81·49
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$i=\frac{-b}{2a}=\frac{-126}{162}=-7/9$

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