(7+9i)(7+9i)=0

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Solution for (7+9i)(7+9i)=0 equation:



(7+9i)(7+9i)=0
We add all the numbers together, and all the variables
(9i+7)(9i+7)=0
We multiply parentheses ..
(+81i^2+63i+63i+49)=0
We get rid of parentheses
81i^2+63i+63i+49=0
We add all the numbers together, and all the variables
81i^2+126i+49=0
a = 81; b = 126; c = +49;
Δ = b2-4ac
Δ = 1262-4·81·49
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$i=\frac{-b}{2a}=\frac{-126}{162}=-7/9$

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