(7+b)+3=7+(b+3)

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Solution for (7+b)+3=7+(b+3) equation: 



(7+b)+3=7+(b+3)

We move all terms to the left:

(7+b)+3-(7+(b+3))=0

We add all the numbers together, and all the variables

(b+7)-(7+(b+3))+3=0

We get rid of parentheses

b-(7+(b+3))+7+3=0



We calculate terms in parentheses: -(7+(b+3)), so:

7+(b+3)

determiningTheFunctionDomain
(b+3)+7

We get rid of parentheses

b+3+7

We add all the numbers together, and all the variables

b+10

Back to the equation:

-(b+10)



We add all the numbers together, and all the variables

b-(b+10)+10=0

We get rid of parentheses

b-b-10+10=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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