(7+u)(2u+3)=0

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Solution for (7+u)(2u+3)=0 equation:


Simplifying
(7 + u)(2u + 3) = 0

Reorder the terms:
(7 + u)(3 + 2u) = 0

Multiply (7 + u) * (3 + 2u)
(7(3 + 2u) + u(3 + 2u)) = 0
((3 * 7 + 2u * 7) + u(3 + 2u)) = 0
((21 + 14u) + u(3 + 2u)) = 0
(21 + 14u + (3 * u + 2u * u)) = 0
(21 + 14u + (3u + 2u2)) = 0

Combine like terms: 14u + 3u = 17u
(21 + 17u + 2u2) = 0

Solving
21 + 17u + 2u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(7 + u)(3 + 2u) = 0

Subproblem 1

Set the factor '(7 + u)' equal to zero and attempt to solve: Simplifying 7 + u = 0 Solving 7 + u = 0 Move all terms containing u to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + u = 0 + -7 Combine like terms: 7 + -7 = 0 0 + u = 0 + -7 u = 0 + -7 Combine like terms: 0 + -7 = -7 u = -7 Simplifying u = -7

Subproblem 2

Set the factor '(3 + 2u)' equal to zero and attempt to solve: Simplifying 3 + 2u = 0 Solving 3 + 2u = 0 Move all terms containing u to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + 2u = 0 + -3 Combine like terms: 3 + -3 = 0 0 + 2u = 0 + -3 2u = 0 + -3 Combine like terms: 0 + -3 = -3 2u = -3 Divide each side by '2'. u = -1.5 Simplifying u = -1.5

Solution

u = {-7, -1.5}

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