(7+u)(2u-1)=0

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Solution for (7+u)(2u-1)=0 equation:


Simplifying
(7 + u)(2u + -1) = 0

Reorder the terms:
(7 + u)(-1 + 2u) = 0

Multiply (7 + u) * (-1 + 2u)
(7(-1 + 2u) + u(-1 + 2u)) = 0
((-1 * 7 + 2u * 7) + u(-1 + 2u)) = 0
((-7 + 14u) + u(-1 + 2u)) = 0
(-7 + 14u + (-1 * u + 2u * u)) = 0
(-7 + 14u + (-1u + 2u2)) = 0

Combine like terms: 14u + -1u = 13u
(-7 + 13u + 2u2) = 0

Solving
-7 + 13u + 2u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(-7 + -1u)(1 + -2u) = 0

Subproblem 1

Set the factor '(-7 + -1u)' equal to zero and attempt to solve: Simplifying -7 + -1u = 0 Solving -7 + -1u = 0 Move all terms containing u to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -1u = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -1u = 0 + 7 -1u = 0 + 7 Combine like terms: 0 + 7 = 7 -1u = 7 Divide each side by '-1'. u = -7 Simplifying u = -7

Subproblem 2

Set the factor '(1 + -2u)' equal to zero and attempt to solve: Simplifying 1 + -2u = 0 Solving 1 + -2u = 0 Move all terms containing u to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -2u = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -2u = 0 + -1 -2u = 0 + -1 Combine like terms: 0 + -1 = -1 -2u = -1 Divide each side by '-2'. u = 0.5 Simplifying u = 0.5

Solution

u = {-7, 0.5}

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