(7+u)(2u-3)=0

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Solution for (7+u)(2u-3)=0 equation:


Simplifying
(7 + u)(2u + -3) = 0

Reorder the terms:
(7 + u)(-3 + 2u) = 0

Multiply (7 + u) * (-3 + 2u)
(7(-3 + 2u) + u(-3 + 2u)) = 0
((-3 * 7 + 2u * 7) + u(-3 + 2u)) = 0
((-21 + 14u) + u(-3 + 2u)) = 0
(-21 + 14u + (-3 * u + 2u * u)) = 0
(-21 + 14u + (-3u + 2u2)) = 0

Combine like terms: 14u + -3u = 11u
(-21 + 11u + 2u2) = 0

Solving
-21 + 11u + 2u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(-7 + -1u)(3 + -2u) = 0

Subproblem 1

Set the factor '(-7 + -1u)' equal to zero and attempt to solve: Simplifying -7 + -1u = 0 Solving -7 + -1u = 0 Move all terms containing u to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -1u = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -1u = 0 + 7 -1u = 0 + 7 Combine like terms: 0 + 7 = 7 -1u = 7 Divide each side by '-1'. u = -7 Simplifying u = -7

Subproblem 2

Set the factor '(3 + -2u)' equal to zero and attempt to solve: Simplifying 3 + -2u = 0 Solving 3 + -2u = 0 Move all terms containing u to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -2u = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -2u = 0 + -3 -2u = 0 + -3 Combine like terms: 0 + -3 = -3 -2u = -3 Divide each side by '-2'. u = 1.5 Simplifying u = 1.5

Solution

u = {-7, 1.5}

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