(7+u)(4u+1)=0

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Solution for (7+u)(4u+1)=0 equation:


Simplifying
(7 + u)(4u + 1) = 0

Reorder the terms:
(7 + u)(1 + 4u) = 0

Multiply (7 + u) * (1 + 4u)
(7(1 + 4u) + u(1 + 4u)) = 0
((1 * 7 + 4u * 7) + u(1 + 4u)) = 0
((7 + 28u) + u(1 + 4u)) = 0
(7 + 28u + (1 * u + 4u * u)) = 0
(7 + 28u + (1u + 4u2)) = 0

Combine like terms: 28u + 1u = 29u
(7 + 29u + 4u2) = 0

Solving
7 + 29u + 4u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(7 + u)(1 + 4u) = 0

Subproblem 1

Set the factor '(7 + u)' equal to zero and attempt to solve: Simplifying 7 + u = 0 Solving 7 + u = 0 Move all terms containing u to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + u = 0 + -7 Combine like terms: 7 + -7 = 0 0 + u = 0 + -7 u = 0 + -7 Combine like terms: 0 + -7 = -7 u = -7 Simplifying u = -7

Subproblem 2

Set the factor '(1 + 4u)' equal to zero and attempt to solve: Simplifying 1 + 4u = 0 Solving 1 + 4u = 0 Move all terms containing u to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 4u = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 4u = 0 + -1 4u = 0 + -1 Combine like terms: 0 + -1 = -1 4u = -1 Divide each side by '4'. u = -0.25 Simplifying u = -0.25

Solution

u = {-7, -0.25}

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