(7+v)(5v+6)=0

Solution for (7+v)(5v+6)=0 equation:

(7+v)(5v+6)=0

We add all the numbers together, and all the variables

(v+7)(5v+6)=0

We multiply parentheses ..

(+5v^2+6v+35v+42)=0

We get rid of parentheses

5v^2+6v+35v+42=0

We add all the numbers together, and all the variables

5v^2+41v+42=0

a = 5; b = 41; c = +42;
Δ = b2-4ac
Δ = 412-4·5·42
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-29}{2*5}=\frac{-70}{10}
=-7
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+29}{2*5}=\frac{-12}{10}
=-1+1/5
$