(7+v)(5v-6)=0

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Solution for (7+v)(5v-6)=0 equation:



(7+v)(5v-6)=0
We add all the numbers together, and all the variables
(v+7)(5v-6)=0
We multiply parentheses ..
(+5v^2-6v+35v-42)=0
We get rid of parentheses
5v^2-6v+35v-42=0
We add all the numbers together, and all the variables
5v^2+29v-42=0
a = 5; b = 29; c = -42;
Δ = b2-4ac
Δ = 292-4·5·(-42)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-41}{2*5}=\frac{-70}{10} =-7 $
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+41}{2*5}=\frac{12}{10} =1+1/5 $

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