(7+w)(2w+1)=0

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Solution for (7+w)(2w+1)=0 equation:



(7+w)(2w+1)=0
We add all the numbers together, and all the variables
(w+7)(2w+1)=0
We multiply parentheses ..
(+2w^2+w+14w+7)=0
We get rid of parentheses
2w^2+w+14w+7=0
We add all the numbers together, and all the variables
2w^2+15w+7=0
a = 2; b = 15; c = +7;
Δ = b2-4ac
Δ = 152-4·2·7
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-13}{2*2}=\frac{-28}{4} =-7 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+13}{2*2}=\frac{-2}{4} =-1/2 $

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