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(7+x)(x-4)=7x-74+x2-4x
We move all terms to the left:
(7+x)(x-4)-(7x-74+x2-4x)=0
We add all the numbers together, and all the variables
-(+3x+x^2-74)+(x+7)(x-4)=0
We get rid of parentheses
-x^2-3x+(x+7)(x-4)+74=0
We multiply parentheses ..
-x^2+(+x^2-4x+7x-28)-3x+74=0
We add all the numbers together, and all the variables
-1x^2+(+x^2-4x+7x-28)-3x+74=0
We get rid of parentheses
-1x^2+x^2-4x+7x-3x-28+74=0
We add all the numbers together, and all the variables
46!=0
There is no solution for this equation
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