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(7+x)4x=139
We move all terms to the left:
(7+x)4x-(139)=0
We add all the numbers together, and all the variables
(x+7)4x-139=0
We multiply parentheses
4x^2+28x-139=0
a = 4; b = 28; c = -139;
Δ = b2-4ac
Δ = 282-4·4·(-139)
Δ = 3008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3008}=\sqrt{64*47}=\sqrt{64}*\sqrt{47}=8\sqrt{47}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-8\sqrt{47}}{2*4}=\frac{-28-8\sqrt{47}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+8\sqrt{47}}{2*4}=\frac{-28+8\sqrt{47}}{8} $
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